2^x=-(1/128)

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Solution for 2^x=-(1/128) equation: 



2^x=-(1/128)

We move all terms to the left:

2^x-(-(1/128))=0

We add all the numbers together, and all the variables

2^x-(-(+1/128))=0

We multiply all the terms by the denominator


2^x*128))-(-(+1=0

Wy multiply elements

256x^2+1=0

a = 256; b = 0; c = +1;
Δ = b2-4ac
Δ = 02-4·256·1
Δ = -1024
Delta is less than zero, so there is no solution for the equation

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